Web1,1,1-Trifluoro-3-methoxypropane, also known as TMFP, is a colorless liquid with a sweet odor. TMFP is widely used in the chemical industry as a solvent and intermediate in the synthesis of pharmaceuticals, agrochemicals, and other fine chemicals. WebQuestion: Question If 1.28 moles of hydrogen react, how many water molecules will be produced, according to the following equation: 3H2 + Fe2O3-+ 2Fe + 3H20 e ... how many water molecules will be produced, according to the following equation: 3H2 + Fe2O3-+ 2Fe + 3H20 e Use 6.022 × 10°, mol-1 for Avogadro's number. . Your answer should have ...
8.2: Stoichiometry - Chemistry LibreTexts
WebTherefore, the number of molecules of H2O is 14.2 moles x 6.02 x 1023, which is 8.42 x 1023 molecules of H2O. QUESTION 7. 7a. 4.88 L N₂ To calculate the volume of N₂ gas produced, we need to calculate the number of moles of NaN first. The mass of NaN is 115 g, so the number of moles of NaN is 115 g ÷ 65.02 g/mol, which is 1.77 moles of NaN. WebWhen 250. mL of a 0.15 M solution of ammonium sulfide (NH 4) 2 S is poured into 120. mL of a 0.053 M solution of cadmium sulfate CdSO 4, how many grams of a yellow precipitate of cadmium sulfide CdS are formed? The other product is (NH 4) 2 SO 4. (Hint: Write out and balance the equation. Is this a limiting reagent problem? ) (a) 5.4 g (b) 0.92 ... inaph entry
Ocl2 - BRAINGITH
Webmolecules = 1.75 mol 23 6.02x10molecules CO x 2 1 mol 24 = 1.05x10molecules (3 sig figs) d) Number of mole of H atoms in 20.0 g of CH 4 Molar mass = 12.0+ 4(1.01)= 16.0 g/mol # of CH 4 molecules = 20.0 g CH 1 mol x 4 16.0 g 4 mo H atoms x 1 mol CH WebB A: 3H, B: 2H, C: 3H Xo H OH. For all of the following molecules, determine how many different types of hydrogens there are and label them on the compounds. In the box below each compound, add your labels with their respective integral values. One molecule has been completed for you. B A: 3H, B: 2H, C: 3H Xo H OH. Web4NH₃ (g) + 7O₂ (g) → 4NO₂ (g) + 6H₂O (l) Step 2. Convert mass of NH₃ → moles of NH₃ → moles of NO₂. 100 g NH₃ × 1mol NH3 17.03g NH3 × 4mol NO2 4mol NH3 = 5.872 mol NH₃ (3 significant figures + 1 guard digit) Step 3. Use the Ideal Gas Law to calculate the volume of NO₂. P V = nRT V = nRT P = 5.872mol × 8.314kPa⋅L⋅K−1mol−1 ×273K 100kPa = 133 L inaph bull id